#include<math.h>
main()
{
double?money,capital; double?rate[4]={0.009,0.01,0.0111,0.012}; int?n; printf("請輸入本金和期限(年)\n"); scanf("%lf%d",&capital,&n); if(n>3) money=capital*pow((1+rate[3]),12*n); else money=capital*pow((1+rate[n-1]),12*n); printf("%d年後本金和利息合計為:%.2lf\n",n,money);?}